The Square and The Peg Theorem S³am
S ³ am Steven Henderson 5/21/26 ORCID #0009-0004-9169-8148 OPERATORS: Ψ | Ω = 2 = 6 = 0 Φ | ϖ | ϗ = 3 = 7 = 1 NINE Ϊ | Ϋ = Α Γ Δ | Ε Ζ Η | Θ Ι Κ | Λ Μ Ν | Ξ Ο Π | Ρ Σ Τ | Υ Φ Χ = 7 ϴ = 1 Ϗ | ϐ | ϑ - ϒ| ϓ | ϔ = 6 SIX δ ε ζ | η θ ι |κ λ μ| ν ξ ο |π ρ ς |σ τ υ |φ χ ψ = 7 Ϩ | ϩ – Ϫ | ϫ - Ϭ |ϭ – Ϯ | ϯ – ϰ | ϱ – ϲ | ϳ = 6 ϴ = 1 THREE ϵ |϶ - Ϸ | ϸ = 3 ϋ | ό |ύ | ώ = 4 α | β | γ = 3 Ϛ| ϛ – Ϝ| ϝ – Ϟ | ϟ – Ϡ | ϡ - Ϣ |ϣ – Ϥ | ϥ – Ϧ | ϧ = 7 ω | ϊ = 2 ά |έ | ή | ί| ΰ = 5 Ϙ |ϙ = 2 PHASE TIME EQUATIONS: ·|Θ = (α + α + α + α + α + α + α) ·|Θ = (ß + α) + (ß + α) + α ·|θ = (ß + α) + (ß · ß) ·|θ = (ß + α) + (ß · ß) Ψ|Φ = (ß + α) · ((ß + α)· (ß + α)) Ψ|Φ = (ß + α) · ((ß + α) · (ß² + α)) Ψ|Φ = (ß + α) · (ß + α) ² Θ = ß + ɛ Θ = ß ((ß + α) · ß + ( (ß + α) · ß) + α) Ɛ = (ß · ß) + α ) + ß (ß + α) Ω|Χ = ß · ((ß + α) · (ß · ß) Ω|Χ = (ß + α) · (ß · ß) ß Ω|Χ = (ß²) + α) · ß Υ = (ß + α) · ((ß + α) · ß) + α) Δ | Ζ ...
