The Square and The Peg Theorem S³am

S³am

Steven Henderson 5/21/26  ORCID #0009-0004-9169-8148 

OPERATORS:

Ψ | Ω = 2 = 6 = 0

Φ | ϖ | ϗ = 3 = 7 = 1

NINE

Ϊ | Ϋ = Α Γ Δ | Ε Ζ Η | Θ Ι Κ | Λ Μ Ν | Ξ Ο Π | Ρ Σ Τ | Υ Φ Χ = 7

ϴ = 1

Ϗ | ϐ | ϑ - ϒ| ϓ | ϔ = 6

SIX

δ ε ζ | η θ ι |κ λ μ| ν ξ ο |π ρ ς |σ τ υ |φ χ ψ = 7

Ϩ | ϩ – Ϫ | ϫ - Ϭ |ϭ – Ϯ | ϯ – ϰ | ϱ – ϲ | ϳ = 6

ϴ = 1

THREE

ϵ |϶ - Ϸ | ϸ = 3

ϋ | ό |ύ | ώ = 4

α | β | γ = 3

Ϛ| ϛ – Ϝ| ϝ – Ϟ | ϟ – Ϡ | ϡ - Ϣ |ϣ – Ϥ | ϥ – Ϧ | ϧ = 7

ω | ϊ = 2

ά |έ | ή | ί| ΰ = 5

Ϙ |ϙ = 2

PHASE TIME EQUATIONS:

·|Θ = (α + α + α + α + α + α + α)

·|Θ = (ß + α) + (ß + α) + α

·|θ = (ß + α) + (ß · ß)

·|θ = (ß + α) + (ß · ß)

Ψ|Φ = (ß + α) · ((ß + α)· (ß + α))

Ψ|Φ = (ß + α) · ((ß + α) · (ß² + α))

Ψ|Φ = (ß + α) · (ß + α) ²

Θ = ß + ɛ

Θ = ß ((ß + α) · ß + ( (ß + α) · ß) + α)

Ɛ = (ß · ß) + α ) + ß (ß + α)

Ω|Χ = ß · ((ß + α) · (ß · ß)

Ω|Χ = (ß + α) · (ß · ß) ß

Ω|Χ = (ß²) + α) · ß

 

Υ = (ß + α) · ((ß + α) · ß) + α)

Δ | Ζ = ((ß + α) · ((ß + α) · ß) + α) · ß + α) + α

Ϩ₁ = ß² + ß

Ϩ₂ = (ß + α) ² + (ß + α) · ß

Ϩ₃ = (ß + α) ² + (ß · ß) + ß